I didn't understand your recursion so much, I wrote one for you, please refer to #intfun (intn) {if (n == 1 || n == 2) Return1; (N-1) FUN (N-2);} intmain (void) {intn, i = 0; "please enter how many items to output the quota:); scanf ("%d ",
I didn't understand your recursion so much, I wrote one for you, please refer to #include u003CSTDIO.H> int Fun (int n) r { if (n == 1 || nnnnnn) Rturn 1; 1)
fun (n-2); } int main (void) { int n, i = 0; printf ("Please enter how many items to output the quota:); scanf ("%d ",
After executing Return, the sentence behind Return will not be executed. can actually write like this int fib (int n) { if (n u003Cu003C= 2) RTurn 1; -1) fib (n-2); } I just write about it, and grasp it by myself
Code:
#include
I didn't understand your recursion so much, I wrote one for you, please refer to
#intfun (intn) {if (n == 1 || n == 2) Return1; (N-1) FUN (N-2);} intmain (void) {intn, i = 0; "please enter how many items to output the quota:); scanf ("%d ",
I didn't understand your recursion so much, I wrote one for you, please refer to
#include
u003CSTDIO.H>
int
Fun (int
n) r
{
if (n == 1
||
nnnnnn)
Rturn
1; 1)
fun (n-2);
}
int
main (void)
{
int
n, i = 0;
printf ("Please enter how many items to output the quota:);
scanf ("%d ",
After executing Return, the sentence behind Return will not be executed.
can actually write like this
int fib (int n)
{
if (n u003Cu003C= 2)
RTurn 1; -1) fib (n-2);
}
I just write about it, and grasp it by myself
scanf ("%d", x);